3.5.23 \(\int \frac {x^5}{(a+b x^3)^{3/2}} \, dx\) [423]

Optimal. Leaf size=38 \[ \frac {2 a}{3 b^2 \sqrt {a+b x^3}}+\frac {2 \sqrt {a+b x^3}}{3 b^2} \]

[Out]

2/3*a/b^2/(b*x^3+a)^(1/2)+2/3*(b*x^3+a)^(1/2)/b^2

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Rubi [A]
time = 0.02, antiderivative size = 38, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 2, integrand size = 15, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.133, Rules used = {272, 45} \begin {gather*} \frac {2 a}{3 b^2 \sqrt {a+b x^3}}+\frac {2 \sqrt {a+b x^3}}{3 b^2} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[x^5/(a + b*x^3)^(3/2),x]

[Out]

(2*a)/(3*b^2*Sqrt[a + b*x^3]) + (2*Sqrt[a + b*x^3])/(3*b^2)

Rule 45

Int[((a_.) + (b_.)*(x_))^(m_.)*((c_.) + (d_.)*(x_))^(n_.), x_Symbol] :> Int[ExpandIntegrand[(a + b*x)^m*(c + d
*x)^n, x], x] /; FreeQ[{a, b, c, d, n}, x] && NeQ[b*c - a*d, 0] && IGtQ[m, 0] && ( !IntegerQ[n] || (EqQ[c, 0]
&& LeQ[7*m + 4*n + 4, 0]) || LtQ[9*m + 5*(n + 1), 0] || GtQ[m + n + 2, 0])

Rule 272

Int[(x_)^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> Dist[1/n, Subst[Int[x^(Simplify[(m + 1)/n] - 1)*(a
+ b*x)^p, x], x, x^n], x] /; FreeQ[{a, b, m, n, p}, x] && IntegerQ[Simplify[(m + 1)/n]]

Rubi steps

\begin {align*} \int \frac {x^5}{\left (a+b x^3\right )^{3/2}} \, dx &=\frac {1}{3} \text {Subst}\left (\int \frac {x}{(a+b x)^{3/2}} \, dx,x,x^3\right )\\ &=\frac {1}{3} \text {Subst}\left (\int \left (-\frac {a}{b (a+b x)^{3/2}}+\frac {1}{b \sqrt {a+b x}}\right ) \, dx,x,x^3\right )\\ &=\frac {2 a}{3 b^2 \sqrt {a+b x^3}}+\frac {2 \sqrt {a+b x^3}}{3 b^2}\\ \end {align*}

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Mathematica [A]
time = 0.02, size = 27, normalized size = 0.71 \begin {gather*} \frac {2 \left (2 a+b x^3\right )}{3 b^2 \sqrt {a+b x^3}} \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[x^5/(a + b*x^3)^(3/2),x]

[Out]

(2*(2*a + b*x^3))/(3*b^2*Sqrt[a + b*x^3])

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Maple [A]
time = 0.15, size = 35, normalized size = 0.92

method	result	size
gosper	\(\frac {\frac {2 b \,x^{3}}{3}+\frac {4 a}{3}}{\sqrt {b \,x^{3}+a}\, b^{2}}\)	\(24\)
trager	\(\frac {\frac {2 b \,x^{3}}{3}+\frac {4 a}{3}}{\sqrt {b \,x^{3}+a}\, b^{2}}\)	\(24\)
risch	\(\frac {2 a}{3 b^{2} \sqrt {b \,x^{3}+a}}+\frac {2 \sqrt {b \,x^{3}+a}}{3 b^{2}}\)	\(31\)
default	\(\frac {2 a}{3 b^{2} \sqrt {\left (x^{3}+\frac {a}{b}\right ) b}}+\frac {2 \sqrt {b \,x^{3}+a}}{3 b^{2}}\)	\(35\)
elliptic	\(\frac {2 a}{3 b^{2} \sqrt {\left (x^{3}+\frac {a}{b}\right ) b}}+\frac {2 \sqrt {b \,x^{3}+a}}{3 b^{2}}\)	\(35\)

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^5/(b*x^3+a)^(3/2),x,method=_RETURNVERBOSE)

[Out]

2/3/b^2*a/((x^3+a/b)*b)^(1/2)+2/3*(b*x^3+a)^(1/2)/b^2

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Maxima [A]
time = 0.29, size = 30, normalized size = 0.79 \begin {gather*} \frac {2 \, \sqrt {b x^{3} + a}}{3 \, b^{2}} + \frac {2 \, a}{3 \, \sqrt {b x^{3} + a} b^{2}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^5/(b*x^3+a)^(3/2),x, algorithm="maxima")

[Out]

2/3*sqrt(b*x^3 + a)/b^2 + 2/3*a/(sqrt(b*x^3 + a)*b^2)

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Fricas [A]
time = 0.36, size = 35, normalized size = 0.92 \begin {gather*} \frac {2 \, {\left (b x^{3} + 2 \, a\right )} \sqrt {b x^{3} + a}}{3 \, {\left (b^{3} x^{3} + a b^{2}\right )}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^5/(b*x^3+a)^(3/2),x, algorithm="fricas")

[Out]

2/3*(b*x^3 + 2*a)*sqrt(b*x^3 + a)/(b^3*x^3 + a*b^2)

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Sympy [A]
time = 0.31, size = 46, normalized size = 1.21 \begin {gather*} \begin {cases} \frac {4 a}{3 b^{2} \sqrt {a + b x^{3}}} + \frac {2 x^{3}}{3 b \sqrt {a + b x^{3}}} & \text {for}\: b \neq 0 \\\frac {x^{6}}{6 a^{\frac {3}{2}}} & \text {otherwise} \end {cases} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x**5/(b*x**3+a)**(3/2),x)

[Out]

Piecewise((4*a/(3*b**2*sqrt(a + b*x**3)) + 2*x**3/(3*b*sqrt(a + b*x**3)), Ne(b, 0)), (x**6/(6*a**(3/2)), True)
)

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Giac [A]
time = 1.56, size = 33, normalized size = 0.87 \begin {gather*} \frac {2 \, {\left (\frac {\sqrt {b x^{3} + a}}{b} + \frac {a}{\sqrt {b x^{3} + a} b}\right )}}{3 \, b} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^5/(b*x^3+a)^(3/2),x, algorithm="giac")

[Out]

2/3*(sqrt(b*x^3 + a)/b + a/(sqrt(b*x^3 + a)*b))/b

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Mupad [B]
time = 1.14, size = 24, normalized size = 0.63 \begin {gather*} \frac {2\,b\,x^3+4\,a}{3\,b^2\,\sqrt {b\,x^3+a}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^5/(a + b*x^3)^(3/2),x)

[Out]

(4*a + 2*b*x^3)/(3*b^2*(a + b*x^3)^(1/2))

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